LeetCode
LeetCode 1169 Invalid Transactions - Medium
1169. Invalid Transactions -- Medium
1169. Invalid Transactions — Medium
Problem
- Invalid Transactions -- Medium
A transaction is possibly invalid if:
the amount exceeds $1000, or; if it occurs within (and including) 60 minutes of another transaction with the same name in a different city. Each transaction string transactions[i] consists of comma separated values representing the name, time (in minutes), amount, and city of the transaction.
Given a list of transactions, return a list of transactions that are possibly invalid. You may return the answer in any order.
Example 1: Input: transactions = ["alice,20,800,mtv","alice,50,100,beijing"] Output: ["alice,20,800,mtv","alice,50,100,beijing"] Explanation: The first transaction is invalid because the second transaction occurs within a difference of 60 minutes, have the same name and is in a different city. Similarly the second one is invalid too.
Example 2: Input: transactions = ["alice,20,800,mtv","alice,50,1200,mtv"] Output: ["alice,50,1200,mtv"]
Example 3: Input: transactions = ["alice,20,800,mtv","bob,50,1200,mtv"] Output: ["bob,50,1200,mtv"]
Constraints: transactions.length <= 1000 Each transactions[i] takes the form "{name},{time},{amount},{city}" Each {name} and {city} consist of lowercase English letters, and have lengths between 1 and 10. Each {time} consist of digits, and represent an integer between 0 and 1000. Each {amount} consist of digits, and represent an integer between 0 and 2000.
Solution
class Solution:
def invalidTransactions(self, transactions: List[str]) -> List[str]:
invalid=set()
for i in range(len(transactions)):
name1,time1,amount1,city1=transactions[i].split(",")
if int(amount1)> 1000:
invalid.add(transactions[i])
#continue
for j in range(i+1,len(transactions)):
name2,time2,amount2,city2=transactions[j].split(",")
if name1 == name2 and abs(int(time1)-int(time2)) <= 60 and city1!=city2:
invalid.add(transactions[i])
invalid.add(transactions[j])
return list(invalid)