LeetCode
LeetCode 98 Valid Binary Search Tree - Medium
98. Validate Binary Search Tree -- Medium
98. Valid Binary Search Tree — Medium
Problem
- Validate Binary Search Tree -- Medium
Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys greater than the node's key. Both the left and right subtrees must also be binary search trees.
Example 1:
2
/
1 3
Input: [2,1,3] Output: true Example 2:
5
/
1 4
/
3 6
Input: [5,1,4,null,null,3,6] Output: false Explanation: The root node's value is 5 but its right child's value is 4.
Solution
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def isValidBST(self, root: TreeNode) -> bool:
lower = float('-inf')
upper = float('inf')
return self.dfs(root, lower, upper)
def dfs(self, node, lower, upper):
if not node:
return True
if node.val <= lower or node.val >= upper:
return False
if not self.dfs(node.left, lower, node.val):
return False
if not self.dfs(node.right, node.val, upper):
return False
return True